Chugging along
September 12, 2011 at 16:35 | Posted in Uncategorized | Leave a commentKeeping the notation the same as in the last post, we begin our quest to prove . The proof is not surprising. Start by letting
be a family of cardinality “covering all small products”. We let be a sufficiently large regular cardinal, and let be an elementary submodel of containing the relevant parameters, with
Our plan is to prove that
is a family satisfying the needed “covering requirements”. Said another way, we will prove that any element of can be covered by a union of fewer than sets from . Since
this will establish .
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